A homework....

3.1 Answer)

Total energy E_t=1/2mv²+mgz+U+pV

Potential energy charges are negligible, so we get,
E_t = 1/2mv²+H (H - Enthalpy)

Entering energy per 1 second is given by following equation
E₁=1/2mv₁²+H₁

The energy theta exiting flow has is given by following equation
E₂=1/2mv₂²+H₂


We can neglect the heat loss, we get the power generated per 1 sec. by following equation

P_[J/s]   = E₁ - E₂ = 1.8［1/2(20²-38²)+(3140-2500)×10³］=1151060.4 = 1151 kW